# Anchorage capacity of one welded transverse bar following the EN Eurocode recommendation, `F`_{btd}

_{btd}

## Eurocode 2 part 1-1: Design of concrete structures 8.6 (2)

The recommended value for the anchorage capacity of one welded transverse bar (diameter 14 mm - 32 mm) is:

F = _{btd}l _{td}Φ _{t}σ ≤ _{td}F_{wd} | (8.8N) |

where:

`Φ`_{t}- is the diameter of transverse bar
`σ`_{td}- is the concrete stress;
`σ`= (_{td}`f`+_{ctd}`σ`)/_{cm}`y`≤ 3`f`_{cd}

with`f`_{cd}- the design compressive strength of concrete, see § 3.1.6 (1)P
`f`_{ctd}- the design tensile strength of concrete, see § 3.1.6 (2)P
`σ`_{cm}- the compression in the concrete perpendicular to both bars (mean value, positive for compression)

`y`- is a function:
`y`= 0,015 + 0,14⋅e^{(-0,18x)}

where`x`= 2(`c`/`Φ`+ 1)_{t}

`c`is the concrete cover perpendicular to both bars.

`l`_{td}- is the design length of transverse bar:
`l`= 1,16_{td}`Φ`(_{t}`f`/_{yd}`σ`)_{td}^{0,5}≤`l`_{t}

with`f`_{yd}- the design yield strength of transverse bar,
`f`=_{yd}`f`/_{yk}`γ`_{S}

see § 2.4.2.4 (1), § 2.4.2.4 (2) for the values of`γ`,_{S}

see § 3.2.2 (3)P for the uper limit of`f`,_{yk}

see Figure 3.8 for the design stress-strain diagrams of reinforcement steel `l`_{t}- the length of transverse bar, but not more than the spacing of bars to be anchored.

`F`_{wd}- is the design shear strength of weld,
`F`=_{wd}`k`_{w}`A`_{s,l}`f`_{yd,l}

with`k`_{w}- a factor, for example
`k`= 0,5_{w} `A`_{s,l}- the cross-section of the anchored bar
`f`_{yd,l}- the design yield strength of the anchored bar.

This application calculates
the anchorage capacity `F _{btd}`
from your inputs.
Intermediate results will also be given.