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Anchorage capacity of one welded transverse bar following the EN Eurocode recommendation, Fbtd

Eurocode 2 part 1-1: Design of concrete structures  8.6 (2)

The recommended value for the anchorage capacity of one welded transverse bar (diameter 14 mm - 32 mm) is:

Fbtd = ltd Φt σtd  ≤ Fwd (8.8N)

where:

Φt
is the diameter of transverse bar
σtd
is the concrete stress; σtd = (fctd + σcm)/y ≤ 3fcd
with
fcd
the design compressive strength of concrete, see § 3.1.6 (1)P
fctd
the design tensile strength of concrete, see § 3.1.6 (2)P
σcm
the compression in the concrete perpendicular to both bars (mean value, positive for compression)
y
is a function: y = 0,015 + 0,14⋅e(-0,18x)
  where x = 2(c/Φt + 1)
   c  is the concrete cover perpendicular to both bars.
ltd
is the design length of transverse bar: ltd = 1,16Φt(fyd/σtd)0,5lt
with
fyd
the design yield strength of transverse bar, fyd = fyk/γS
see § 2.4.2.4 (1), § 2.4.2.4 (2) for the values of γS,
see § 3.2.2 (3)P for the uper limit of fyk,
see Figure 3.8 for the design stress-strain diagrams of reinforcement steel
lt
the length of transverse bar, but not more than the spacing of bars to be anchored.
Fwd
is the design shear strength of weld, Fwd = kwAs,lfyd,l
with
kw
a factor, for example kw = 0,5
As,l
the cross-section of the anchored bar
fyd,l
the design yield strength of the anchored bar.

This application calculates the anchorage capacity Fbtd from your inputs. Intermediate results will also be given.

Input
mm
mm
mm
MPa
MPa
MPa
MPa
mm2
MPa
Output
x
y
σtd
MPa
ltd
mm
ltd Φt σtd
kN
Fwd
kN
the anchorage capacity Fbtd
kN (8.8N)