# Resistance of members subjected to torsion and shear

## Eurocode 2 part 1-1: Design of concrete structures 6.3.2 (4)

The resistance of a member subjected to torsion and shear is limited by the capacity of the concrete struts. The following condition should be satisfied:

T / _{Ed}T + _{Rd,max}V / _{Ed}V ≤ 1,0 _{Rd,max} | (6.29) |

where:

`T`_{Ed}- is the design torsional moment
`V`_{Ed}- is the design transverse force
`T`_{Rd,max}- is the design torsional resistance moment,

`T`= 2_{Rd,max}`ν``α`_{cw}`f`_{cd}`A`_{k}`t`sin_{ef,i}`θ`cos`θ`(6.30) with

`ν`- the strength reduction factor for concrete cracked in shear, see § 6.2.2 (6) for national choice
`α`_{cw}- see Note 3 in § 6.2.3 (3)
`f`_{cd}- the design compressive strength of concrete, see § 3.1.6 (1)P
`A`_{k}- the area enclosed by the centre-lines of the connecting walls, including inner hollow areas, see Figure 6.11
`t`_{ef,i}- the effective wall thickness, see Figure 6.11
`θ`- the angle of compression struts,

see Figure 6.5 for description,

see § 6.2.3 (2) for national choice.

`V`_{Rd,max}- is the maximum design shear resistance, according to:

• Expressions (6.9) for members with vertical shear reinforcement,

• Expressions (6.14) for members with inclined shear reinforcement.

This application calculates the resistance to torsion and shear from your inputs. Intermediate results will also be given.