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# Resistance of members subjected to torsion and shear

## Eurocode 2 part 1-1: Design of concrete structures \$(document).ready(function () { var freeExample = \$("#freeExample").length; \$("#mainMenu li#nav-appCate, #mainMenu li#nav-appEC211").addClass("active"); var proUser = false === true || false === true || freeExample !== 0; if (!proUser) { \$('#Input input').keyup(function(){ \$('#AlertSubscribe').modal(); }); \$('#Input select').change(function(){ \$('#AlertSubscribe').modal(); }); }; var tempInput = \$("#tempInput").text(); if (tempInput != "") { \$("#Input").parent("form").deserialize(tempInput); if (proUser) { \$("#acceptBtn").trigger("click"); } }; });  6.3.2 (4)

The resistance of a member subjected to torsion and shear is limited by the capacity of the concrete struts. The following condition should be satisfied:

 TEd / TRd,max + VEd / VRd,max ≤ 1,0 (6.29)

where:

TEd
is the design torsional moment
VEd
is the design transverse force
TRd,max
is the design torsional resistance moment,
 TRd,max = 2 ν αcw fcd Ak tef,i sinθ cosθ (6.30)

with

ν
the strength reduction factor for concrete cracked in shear, see § 6.2.2 (6) for national choice
αcw
see Note 3 in § 6.2.3 (3)
fcd
the design compressive strength of concrete, see § 3.1.6 (1)P
Ak
the area enclosed by the centre-lines of the connecting walls, including inner hollow areas, see Figure 6.11
tef,i
the effective wall thickness, see Figure 6.11
θ
the angle of compression struts,
see Figure 6.5 for description,
see § 6.2.3 (2) for national choice.
VRd,max
is the maximum design shear resistance, according to:
Expressions (6.9) for members with vertical shear reinforcement,
Expressions (6.14) for members with inclined shear reinforcement.

This application calculates the resistance to torsion and shear from your inputs. Intermediate results will also be given.

Input
MPa
kNm
kN
kN
cm2
cm

Output
θ
°
TRd,max
kNm (6.30)
TEd / TRd,max + VEd / VRd,max
the resistance to torsion and shear
(6.29)