For full functionality of this site it is necessary to enable JavaScript. Here are the instructions how to enable JavaScript in your web browser.

b9. Design method for longitudinal reinforcements of a rectangular section in bending at the SLS, Asc and As

Eurocode 2 - Design of concrete sections


Figure b9-1 introduces a reinforced concrete section with notations. The reinforcements Asc and As are unknown.

Assumptions

1. Plane sections remain plane after straining, so that there is a linear distribution of strains across the section.

2. Reinforcing steels have the same deformation as the nearby concrete.

3. The tensile strength of concrete is ignored.

4. A triangular distribution of the compressive stress in the concrete is assumed.

5. The serviceability limit state occurs when the tensile stress in the reinforcement reaches the limit σs,ser = k3fyk (Pivot A) and/or the compressive stress in the concrete reaches the limit σc,ser = k1fck (Pivot B). The parameters k1 and k3 are chosen by National Annex, see § 7.2 (2) and § 7.2 (5) respectively.


Considering the depth of the neutral axis/the effective depth of the cross-section:

αser = x/d (b9.1)

The linear distribution of strains and the stress diagram gives:

αser = εc/(εc + εs) = ne σc/(ne σc + σs) (b9.2)

where:

ne
is the effective modular ratio
ne = Es / Ec,eff

with:

Es
the design value of the modulus of elasticity of the reinforcing steel, see § 3.2.7 (4)
Ec,eff
the effective modulus of elasticity for concrete.

Balanced section AB

We consider a balanced section for which the Pivot A and Pivot B are reached at the same time: σs = σs,ser and σc = σc,ser.

For the balanced section, calculating:

αAB = ne σc,ser/(ne σc,ser + σs,ser) (b9.3)

If αser > αAB ⇔ the Pivot B is reached first. Otherwise, the Pivot A is reached first.

Serviceability limit state at Pivot B

For equilibrium, the ultimate design moment must be balanced by the moment of resistance of the section:

Mser = Fc z = 0,5 b σc,ser x (d - x/3) = 0,5 b d2 σc,ser αc,ser (1 - αc,ser/3) (b9.4)

Substituting the following in (b9.4):

μc,ser = Mser /(b d2 σc,ser) (b9.5)

(b9.4) ⇒ μc,ser = 0,5 αc,ser ( 1 - αc,ser/3)

αc,ser2 - 3 αc,ser + 6 μc,ser = 0 (b9.6)

If μc,ser ≤ 0,375, this quadratic equation has a solution:

αc,ser = 1,5 [1 - (1 - 8 μc,ser/3)0.5] (b9.7)

Serviceability limit state at Pivot A

For equilibrium, the ultimate design moment must be balanced by the moment of resistance of the section:

Mser = Fc z = 0,5 b σc x (d - x/3) = 0,5 b d2 σc αs,ser (1 - αs,ser/3) (b9.8)

The stress σc is deducted from the stress diagram:

σc = σs,ser αs,ser /[ne (1 - αs,ser)] (b9.9)

Calculating:

μs,ser = Mser /(b d2 σs,ser) (b9.10)

Substituting (b9.9) and (b9.10) in (b9.8),
(b9.8) ⇒ μs,ser = 0,5 ne αs,ser2 ( 1 - αs,ser/3)

αs,ser3 - 3 αs,ser2 - 6 ne μs,ser αs,ser + 6 ne μs,ser = 0 (b9.11)

By solving this cubic equation, we get a root αs,ser ∈ (0,1).

αc,ser > αAB ⇒ Pivot B

The tensile reinforcement As may be determined in two ways:

  • Based solely on the Pivot B and no compressive reinforcement will be provided;
  • Based on the balanced section AB. Thus, the tensile reinforcement As is optimized because its stress σs is taken equal to the limit σs,ser. This optimization requires a calculation of the compressive reinforcement Asc.

In the first case, the tensile stress in the reinforcement is deducted from the stress diagram:

σs = ne σc,ser (1 - αc,ser) /αc,ser (b9.12)

The equilibrium of the section allows the calculation of the tensile reinforcement:

As = Mser / [σs d (1 - αc,ser/3)] (b9.13)

In the second case, we consider that the section is an overlap of two fictive sections (see Figure b9-2):

  • One concrete section with only a tensile reinforcement As1 This section reaches the Pivot A and Pivot B at the same time (balanced section).
  • One section with only two reinforcements As2 and Asc.
Doubly-reinforced-rectangular-concrete-section-bending-serviceability-limit-state

The bending moment supported by the first section is equal to:

MAB = 0,5 b d2 αAB σc,ser (1 - αAB/3) (b9.14)

The tensile reinforcement As1 of the first section:

As1 = MAB /[σs,ser d (1 - αAB/3)] (b9.15)

The tensile reinforcement As2 of the second section:

As2 = (Mser - MAB) /[σs,ser (d - d')] (b9.16)

The compressive stress in the reinforcement:

σsc = σs,ser [αAB - d'/d) /(1 - αAB)] (b9.17)

The compressive reinforcement As2:

Asc = As2 σs,ser /σsc (b9.18)

Finally, the total tensile reinforcement is equal to:

As = As1 + As2 (b9.19)

αc,serαAB ⇒ Pivot A

No compressive reinforcement is needed.

The tensile reinforcement is calculated using αs,ser from (b9.11):

As = Mser /[σs,ser d (1 - αs,ser/3)] (b9.20)

Flowchart

Figure b9-3 resumes this design method for a rectangular reinforced concrete section in bending at the serviceability limit state:

Procedure-reinforcements-rectangular-concrete-section-bending-serviceability-limit-state